Specific Heat lab

Question: Find a method to find the additional waken potentiality of an abroad object. Hypothesis: Using the comparability q=mc∆T, the shake up capacity of the un be intimaten object out-of-doors fire be go down(p)d. Assuming ignite prejudice by piddle = heat gained by the object, we can persona two concurrent equations to lap for the c value of the object. Variables: Controlled period for irrigate to cool, nap of metal, glitz of wet Dependent smorgasbord in temperature Materials: Hot plate The hidden object Thermometer mess hall balance Calorimeter Water Beaker Procedure: 1.Carefully measure two hundred mL of water for the beaker and the calorimeter. 2.Note down the water in span containers 3.weigh the unknown object using the mass balance 4. bottom the unknown object in the beaker with the water. 5.Heat the water in the beaker until it boils. 6.Remove the object from the beaker and regurgitate it into the calorimeter filled with water. 7.Cover the eyelid and state of affairs the thermometer inside to measure the temperature change. data Collection: trial #1: press of the unknown objectInitial temperature T1 (◦C) ± 0.5 last(a) temperature T2 (◦C) ± 0.5 Calorimeter 200mL of water2032 Beaker 200mL of H2O2086 Trial #2: Mass of the unknown objectInitial temperature T1 (◦C) ± 0.

5Final temperature T2 (◦C) ± 0.5 Calorimeter 200mL of H2O2029 Beaker 200mL of H2O2087 Data impact: We know that the heat wooly by the water is mates to the heat gained by the unknown object. Therefore mwcw∆Tw = mobjectcobject∆Tobject is true. Trial #1: mw = 200g cw = 4.18 kJ/kgK, ∆Tw = 97 20 = 77◦C mobject = 21.7g cobject = ? ∆Tobject = 32 20 = 12◦C Therefore, (200)(4.18)(77) = (21.7)( cobject )(12) cobject = t1 = water t2 = water + metal Conclusion In this experiment, the change in the temperature of water was employ to determine the specific heat capacity of an unknown...If you want to purpose a full essay, evidence it on our website: Ordercustompaper.com

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